Chalk Dust Company

  

General Information
Home Page
Our Company
Your Instructor
How to Use DVDs
Quick Sketches - Homeschool Students
Quick Sketches - College Students
Frequently Asked Q's
Customer Comments

Product Information
Prices, Ordering & Evaluations
Assessment Test Request
Textbooks & Solutions Guides
Course Outlines, Reviews & Demos

Existing Customers
Quick Start Guide
Assignments
Read Me First
Technical Support
Replacement DVD/CD
Tests and Measurement

Exhibit Schedule
Education Links


Chalk Dust Company
PMB 256
16107 Kensington Dr
Sugar Land, TX 77479-4401

800.588.7564 (USA)
281.265.2495
281.265.3197 fax

sales@chalkdust.com

Algebra 1, 5th Edition
(new program since July 2009)
Corrections and Clarifications
The Section Exercises are at the end of each section. The student will usually have 75 to 120 odd problems per Section from which to choose, but the good news is that only 25-30 problems per section need to be worked. And this will be about every 3rd or 4th odd problem.

Student Solutions Manual. The Chapter 1, Section 1 odd problems start on page 2.

The Mid-Chapter Quiz and End-of-Chapter test for each chapter are fully supported for both even and odd problems and every problem should be worked.

Chapter 2 Test, problem 5. The answer in the solutions guide should be Additive Identity Property.

Section 4.2, problem 9. In the solutions guide, the table of values is incorrect but the graph is accurate. The y-values in the table should be 11, 10, 9, 8, 7.

Section 4.2, problem 13. In the solutions guide, the table of values is incorrect but the graph is accurate. The y-values in the table should be 7, 4, 3, 4, 7.

Chapter 6 Test, problem 9. In the solutions guide, the leading coefficient 9 should not be included in the problem.

Chapter 7, Mid-Chapter Quiz, problem 20.
The area of a rectangle is calculated using the formula, Area = (length)(width).
The area of the shaded rectangle is Area = (x + 3)(x)
The total area of the figure is Area = (x + 10)(x + 3)
The ratio of the area of the shaded region to the total area of the figure is a fraction with the area of the shaded region in the numerator and the total area of the figure in the denominator. Once the fraction is formed, the factors of the (x + 3) cancel leaving the fraction x / (x + 10).

Algebra 1, 2nd edition
from Oct 2000
Corrections and Clarifications
At the end of each section, problems under Integrated Review may be omitted. Problems under Solving Problems may be limited to about 5 to 6 problems. Problems under Explaining Concepts may be omitted.

How to correlate your solutions guide to the textbook.

Solutions to Integrated Review Exercises for Chapters 2-10; Pages 1-54, Index on page 1.

Solutions to Odd-Numbered Exercises for Chapters 1-10; Pages 55-497, Index on pages 55-57.

NOTE: Goldenrod divider page in middle of book

Solutions to Even-Numbered Exercises for Chapters 1-10; Pages 2-371, Index on pages v-vii.

Example of Chapter 1 Text correlation to Solutions Guide:
Odd exercises on pages 55-57
Even exercises on pages 1-16 (after goldenrod divider)
Chapter Test page 79 is missing. If you have a question about a specific problem contact Dana Mosely.

Click here for more information on Solution Guides.

Chapter 1 Test.
Pages 79 and 80 are missing from the Algebra 1 Complete Solutions Guide, and these pages would have covered the end-of-chapter test for Chapter 1, Algebra 1 textbook. Answers to the Chapter 1 Test are in the back of the Algebra 1 textbook on page A39, and step by step solutions are below.

Algebra 1
Chapter Test for Chapter1

  1. (a) 8 and 12/4
    The fraction 12/4 is natural because is reduces to 3.
    (b) -10, 8, and 12/4
    (c) all of the numbers are rational because they can all be written in the form a/b.
  2. -3/5 _____ -| -2 |
    -3/5 ______ -2
    Since -3/5 lies to the right of -2 on the number line, -3/5 is greater than -2, so -3/5 > -2
  3. 16 + (-20)
    16 - 20
    -4
  4. -50 - (-60)
    -50 + 60
    10
  5. 7 + | -3 |
    7 + 3
    10
  6. 64 - (25 - 8)
    64 - (17)
    64 -17
    47
  7. -5(32)
    -160
  8. -72 / -9
    8
  9. (12 + 9) /7
    21 / 7
    3
  10. - (-2) (5) / 10
    - (-10) / 10
    10 / 10
    1
  11. 5/6 - 1/8
    20/24 - 3/24
    17/24
  12. -27 (5/6)
    -9 (5/2)
    -45/2
  13. 7/16 ö 21/28
    7/16 x 28/21
    1/4 x 7/3
    7/12
  14. -8.1/0.3
    -27
  15. -(2/3)2 Notice the base of the exponent is 2/3, so there are two factors of 2/3
    -(2/3) (2/3)
    - 4/9
  16. 35 - (50 ö 52)
    35 - (50 ö 25)
    35 - 2
    33
  17. The Distributive Property
  18. The Multiplicative Inverse Property
  19. The Associative Property of Addition (because the grouping of numbers changed)
  20. The Commutative Property or Multiplication (because the order of the factors changed)
  21. 30/72 working in easy steps, divide 3 into both numerator and denominator to get 10 /24, now divide 2 into both numerator and denominator, 5/12
  22. In the first expression the base of the exponent is 3 but in the second expression the base of the exponent is -3.
  23. Exponentiation (raise 2 to the 3rd power), multiply (3 times 8), subtract (24 from 32)
  24. Answers vary. Among them are 2/3, 4/6, 6/9, 8/12.

Chapter 1 Review, problem 11. In the solutions guide the answer should be -8.5 rather than 8.5.

Chapter 1 Review, problem 67. Please also accept as correct the expression n + 10/8 which is technically more correct than a fraction with n + 10 as the numerator and 8 as the denominator. If it were intended for the numerator to be n + 10, then the punctuation in the sentence would be: The sum of a number and 10, divided by 8.

Section 1.2, problem 124. In the solutions guide, the prime factorization should contain 3 factors of 3.

Section 1.3, page 43, problem 153. The answers for parts "h" and "i" are switched; "h" should be 15 degrees and "i" should be 14 degrees.

Chapter 2 Review, #94. In the solutions guide, the minus sign should be a times sign.

Chapter 2 Review, #99. In the verbal model, the first item should be "Area of rectangle" rather than "Area of triangle."

Section 3.1, #69. In the solutions guide, the division signs should be equal signs. Also, in the 4th step, 4 should be subtracted from both sides rather than added to both sides.

Section 3.1, #71. In the solutions guide, the division signs should be equal signs.

Section 3.2, Integrated Review, problem 7. The answer in the textbook (page A44) is incorrect. The correct answer is x - 4.

Section 3.5, problem 9. The solution requires the use of a technique called factoring which is covered in a later chapter. Please omit the problem.

Section 3.5, problem 65. In the solutions guide, second step, the first term should contain a factor of x.

Section 4.2, problems 79 and 81. In the Solutions Guide, the Xmin values should be negative rather than positive.

Section 4.3, Integrated Review, problem 6. The middle term of the answer in the Solutions Guide is incorrect. The answer should be 3x^2y - xy^2 - 5xy.

Section 4.4, problem 26. The answer in the solutions guide is correct but, in the second to last step, the denominator fraction should be 17/8 rather than 17/18.

Section 6.5, problem 11. The second answer in the solutions guide should be -100/7 rather than 100/7.

Section 6.5, problem 95 (c). In the solutions guide when the monomial factor of -4 is taken out of the trinomial, the middle term should be -20x rather than 20x.

Section 6.5, problem 99 (b). The answer is incorrect in the solutions guide -- t should be 13 rather than 15 and the year should be 2003 rather than 2005. The window settings must be extended up and to the right in order to view and trace to the positive where y=100 (for 100 million passengers). The corresponding x-value (which stands for time) is approximately 13 rather than 15 listed in the solutions guide so the year is 13 years beyond the basis year of 1990, or the year 2003, rather than 2005 listed in the solutions guide.

Section 7.4, problem 51.In the solutions guide, page 306, the product R=8950(96) should be 859,200 rather than 859,000.

Section 7.4, Integrated Review, problem 2. The answer in the solutions guide is not related to the problem in the textbook. The correct answer should be: The domain of the function is 2<x<a because those are the values of x for which the equations makes sense.

Chapter 7 Review, problem 55. The slope of the line is 4 rather than 3. Therefore the coefficients of x in the equations will change accordingly.

Section 8.2, problem 26. The answer in the solutions guide is incorrect. The answer should contain only two factors of the "v" in the numerator.

Chapter 8, Mid Chapter Quiz, problem 10. The denominator of the fraction in the textbook should be x+2.

Chapter 8 Review, problem 32. In the solutions guide, the missing factor should be (x + 2).

Section 10.1, Problem 35. Omit the 2 in the numerator so that the problem matches the solution in the solution guide.

Chapter 10, Mid Chapter Quiz, problems 16 & 19.
Problem 16. In the solutions guide, c=-1 rather than 1 so the discriminant is 53 rather than 45. The conclusion in the solutions guide is the same.
Problem 19. The method of solution in the solutions guide uses a formula which has not been discussed in this course. The method below may be used to solve the problem but it is a bit involved so the problem may abe omitted from the quiz or treated as an extra credit problem. The method of solution below involves a system of equations using the simple interest formula and the quadratic formula.

I1 stands for the interest earned in the first year and I2 stands for the interest earned in the second year.
In the first year,
I1 = prt
I1 = 1500(r)(1)
I1 = 1500 r

In the second year the amount of principal is the original principal, $1500 plus the interest earned in the first year.
The total principal, then, is 1500 + 1500 r, so...
I2 = prt
I2 = (1500 + 1500r)(r)(1)
I2 = 1500r + 1500r^2

The total interest earned over the two years can be calculated by taking the amount in the account after two years, $1669.54, and subtracting the original principle, $1500, you get $169.54.

Therefore,
I1 + I2 = $169.54 and substituting
1500r + 1500r^2 + 1500r = $169.54 The equation is quadratic so
1500r^2 + 3000r - 169.54 = 0

From here use the quadratic formula(and your calculator) to find r = .055, so the interest rate is 5.5%

Chapter 10, Review Exercises, problems 39 and 81.
Problem 39: In the Solutions Guide, the number under the radical sign should be -11 rather than -9.
Problem 81: In the Solutions Guide, the height should be 6 rather than x. That change leads to a solution of x = 295 meters.

Algebra I
(previous Elementary Algebra program)
Corrections and Clarifications
Student Solutions Guide, page 5, Section P.2, problems 19 and 21. The answers for #19 and #21 should be switched. That is, the answer to #19 is 5 and the answer to #21 is 6.

Chapter 2, page 122, Mid-Chapter Quiz, problem 19. The answer in the text (page A30) contains a "k" factor which should not be there.

For the exercises in Discussing Concepts, you are welcome to ask me about items in those segments as needed. An answer key for these segments is not available to us.

Section 3.2, problem 46. In the solutions guide, the problem is written incorrectly as the fractions are reversed. However, the answer of 1/2 is correct.

2x - 3/8 = 5/8
8(2x) - 8(3/8) = 8(5/8)
16x - 3 = 5
16x - 3 + 3 = 5 + 3
16x = 8
16x / 16 = 8 /16
x = 1/2

Chapter 8, Review Exercises, problem 51. The first equation given, y = 3x - 2 is incorrect. It should be y = 4x - 2. The other equations are variations thereof.

TOP OF THE PAGE

Copyright © 1996-2011 Chalk Dust Company
Website design and hosting by Mediawest Online.